To find the inverse
Let consider the given matrix
2 -5 11
1 1 -6 =A(say)
4 -3 8
Let I be the identity matrix of order 3*3
l= 1 0 0
0 1 0
0 0 1
To find the inverse of matrix A we need to apply the formula
A = IA
later it will be like
I=AA(inverse)
Applying following operations
1.R2 interchange with R1
2. R2>R2-2R1
3. R3>R3-4R1
4.R3>R3-R2
5.R2>-R2/7
6.R1>R1-R2
7.R3>R3/9
8.R1>R1-19R3/7
9. R2>R2+23R3/7
By doing several elementary row transformation we get the inverse as
[ -10/63 -32/63 -1/9
1/9 -4/9 1/9
19/63 23/63 1/9]
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