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Answer to Question #288275 in Differential Equations for Jasper
Question #288275
Β Show that the equation π¦ = π₯π π₯ is a solution of the differential equation: π¦ β² β π¦ β π π₯ = 0
Expert's answer
"(xe^x)'-xe^x-e^x=xe^x+e^x-xe^x-e^x=0"
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