Question

 Show that the equation 𝑦 = 𝑥𝑒 𝑥 is a solution of the differential equation: 𝑦 ′ − 𝑦 − 𝑒 𝑥 = 0

Answer 1

$(xe^x)'-xe^x-e^x=xe^x+e^x-xe^x-e^x=0$