Answer to Question #288275 in Differential Equations for Jasper
Question #288275
Show that the equation 𝑦 = 𝑥𝑒 𝑥 is a solution of the differential equation: 𝑦 ′ − 𝑦 − 𝑒 𝑥 = 0
Expert's answer
"(xe^x)'-xe^x-e^x=xe^x+e^x-xe^x-e^x=0"
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