The solution of (D – 3D²D' - 2DD'²) z = 0 is
The auxillary equation:
m−3m2−2m=0m-3m^2-2m=0m−3m2−2m=0
m(3m+1)=0m(3m+1)=0m(3m+1)=0
m1=0,m2=−1/3m_1=0,m_2=-1/3m1=0,m2=−1/3
C.F.=f1(y)+f2(y−x/3)C.F.=f_1(y)+f_2(y-x/3)C.F.=f1(y)+f2(y−x/3)
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