Given equation is
dtdN=τ(N−qN2)
Integrating the above equation
(qN2−N)dN=−τdt
Integrating it,
∫(qN2−N)dN=−∫τdt
Solving it we get,
ln∣1−Nq∣=−τt+C
Putting boundary equations, N(0) = N0
Then we get
ln∣1−N0q∣=C
Hence, we can say that
ln∣1−Nq∣=−τt+ln∣1−N0q∣
It can be written as
ln∣N0(N−q)N(N0−q)∣=τt
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