Question #128480
Solve the initial value Problem
dN/dt = τ (N − N^2/q) N(0) = No, where τ, q are positive. Hence or otherwise, find the solution of the Verhulst model
when t → ∞
1
Expert's answer
2020-08-05T17:55:09-0400

Given equation is

dNdt=τ(NN2q)\frac{dN}{dt} = \tau (N - \frac{N^2}{q})

Integrating the above equation

dN(N2qN)=τdt\frac{dN}{(\frac{N^2}{q} - N)} = - \tau dt


Integrating it,

dN(N2qN)=τdt\int \frac{dN}{(\frac{N^2}{q} - N)} = - \int\tau dt

Solving it we get,

ln1qN=τt+Cln|1-\frac{q}{N}| = -\tau t + C


Putting boundary equations, N(0) = N0

Then we get

ln1qN0=Cln|1-\frac{q}{N_0}| = C



Hence, we can say that

ln1qN=τt+ln1qN0ln|1-\frac{q}{N}| = -\tau t + ln|1-\frac{q}{N_0}|


It can be written as

lnN(N0q)N0(Nq)=τtln|\frac{N(N_0-q)}{N_0(N-q) }| = \tau t


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