Question #113702
Solve z = (x – y)∅ (x² + y²)
1
Expert's answer
2020-05-05T18:33:52-0400

z=(xy)ϕ(x2+y2)z=(x-y)\phi(x^2+y^2)

Let's denote z/x=p,z/y=q\partial z/\partial x=p, \,\, \partial z/\partial y=q.

Differentiate both sides with respect to xx then to yy:

p=(xy)ϕ(x2+y2)2x+ϕ(x2+y2)p=(x-y) \phi'(x^2+y^2)2x+\phi(x^2+y^2),

q=(xy)ϕ(x2+y2)2yϕ(x2+y2)q=(x-y) \phi'(x^2+y^2)2y-\phi(x^2+y^2).

Hence, we have

pϕ(x2+y2)q+ϕ(x2+y2)=xypyqx=ϕ(x2+y2)(x+y)\frac{p-\phi(x^2+y^2)}{q+\phi(x^2+y^2)}=\frac{x}{y} \rightsquigarrow py-qx=\phi(x^2+y^2)(x+y)


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