a) Let zn=1−1/n∈A, since for all n∈N Rezn<1.
a=n→∞limzn=1∈/A, because Rea=1 and Ima=0<1. Therefore, the set A is not closed.
b) Let zn be an arbitrary sequence in B converging to a limit b=n→∞limzn.
∣Reb−Rezn∣=∣Re(b−zn)∣≤∣b−zn∣→0. Then Reb=n→∞limRezn≤3.
So, b∈B and therefore, B is a closed set.
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