Question #235596

Find the laurent series about the indicated singularity for the function e2z/(z-1)3 at z=1


1
Expert's answer
2021-09-17T03:45:05-0400

f(z)=e2z(z1)3f(z)=\frac {e^{2z}}{(z-1)^3} ,


Let the given complex function be analytic in an annulus r<z1<Rr<|z−1|<R  Then f(z)f(z) can be expanded into Laurent's series about z=1z=1


Let z1=uz-1 =u , then z=u+1,z = u+1, Putting in f(z)f(z) and expanding


f(z)=1u3[1+2(u+1)+2(u+1)2+...]f(z)=\frac {1}{u^3}[1+2(u+1)+2(u+1)^2+...]


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