Question #118256

Find the Cartesian equation of the locus of the point P representing the complex

number z. Sketch the locus of P in each case.

(a) 2|z + 1| = |z − 2|

Expert's answer

2∣z+1∣=∣z−2∣2|z+1|=|z-2|

2∣x+iy+1∣=∣x+iy−2∣2|x+iy+1|=|x+iy-2|

22∣(x+1)+iy∣2=∣(x−2)+iy∣22^2|(x+1)+iy|^2=|(x-2)+iy|^2

4((x+1)2+y2)=(x−2)2+y24((x+1)^2+y^2)=(x-2)^2+y^2

4x2+8x+4+4y2=x2−4x+4+y24x^2+8x+4+4y^2=x^2-4x+4+y^2

3x2+12x+3y2=03x^2+12x+3y^2=0

x2+4x+y2=0x^2+4x+y^2=0

(x2+4x+4)+y2=4(x^2+4x+4)+y^2=4

(x+2)2+y2=4(x+2)^2+y^2=4


Answer: the locus is a circle with center (−2,0)(-2,0) and radius 22 .


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