F(x) = 2x3 + cx2 + 2x.
Suppose f is differentiable on R and has two roots. Show that f' has at least one root.
We say that "f" has roots at "a" and "b, (a<b)," and since "f" is continuous and differentiable everywhere as polynomial, it is continuous on "[a, b]" and differentiable on "(a, b)." So by the Rolle’s theorem, there is a number "k" in "(a, b)," such that "f'(k)=0." Therefore, "k" is a root of "f'(x)=0."
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