Question #334687

F(x) = 2x3 + cx2 + 2x.

Suppose f is differentiable on R and has two roots. Show that f' has at least one root.


1
Expert's answer
2022-04-28T17:42:02-0400

We say that ff has roots at aa and b,(a<b),b, (a<b), and since ff is continuous and differentiable everywhere as polynomial, it is continuous on [a,b][a, b] and differentiable on (a,b).(a, b). So by the Rolle’s theorem, there is a number kk in (a,b),(a, b), such that f(k)=0.f'(k)=0. Therefore, kk is a root of f(x)=0.f'(x)=0.


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