A. Tell whether each given function has a solution on the indicated closed interval. Prove using the Intermediate value theorem.
1. f(x)=3x²+2x²;[-1,1]
2. f(x)= 2-x²/x²;[-3,-1]
B. Sketch the graph of the following functions and then find the absolute extreme values of each of the given interval.
1.f(x)=√x²-25;[5,10]
2. f(x)=-1/x²;[0.5,2]
C. A restaurant's profit function (in hundreds) for hamburgers is given by the function P such that P(x)=1.22x-x²/30,000-4,000,where 0≤x≤20,000.
1. How many hamburgers does the restaurant need to sell to yield the maximum profit?
2. What is the maximum profit from the sale of hamburger ?
Solution (A)
Given that
"f(x)=3x^3+2x" with in interval "[-1,1]"
"f(-1)=3(-1)^3+2(-1)=-5<0"
"f(1)=3(1)^3+2(1)=5>0"
Since
"f(-1)<0" and "f(1)>0"
Therefore, according to IVT the function "f(x)=3x^3+2x" has a solution within the interval "[-1,1]"
The plot above shows that the function "f(x)=3x^3+2x" has a solution within the interval "[-1,1]", which is "x=0"
for the function
"g(x)=\\sqrt{x^2-25}" with in the interval "[5, 10]" , the plot is shown below
From the plot, the extreme values are
The maximum value is "8.66" at "x=10"
The minimum value is at "x=5"
Now For the function
"h(x)=-\\frac{1}{x^2}" within the interval "[0.5,2]"
The plot is shown below
From the plot, the extreme values are
The maximum value is "-0.25" at "x=2"
The minimum value is "-4" at "x=0.5"
"p(x)=1.22x-\\frac{x^2}{30000}-4000" with in the interval "[0, 20000]" , the plot is showb below
From the plot,
The maximum profit is 7163
And the hamburger sold were 18300
Comments
Leave a comment