Answer to Question #280256 in Calculus for Alibaba

Question #280256

If y=sin(2x)/x and x =Pi and ex=.25 find the differentaite


1
Expert's answer
2022-01-25T17:15:43-0500

Solution;

Given;

x=π

ex=0.25e^x=0.25

y=sin(2x)xy=\frac{sin(2x)}{x}

ln(ex)=ln(0.25)ln(e^x)=ln(0.25)

x=ln(0.25)x=ln(0.25)

Apply quotient rule;

dydx=2xcos(2x)sin(2x)x2\frac{dy}{dx}=\frac{2xcos(2x)-sin(2x)}{x^2}

At x=π;

dydx=2πcos(2π)sin(2π)π2\frac{dy}{dx}=\frac{2πcos(2π)-sin(2π)}{π^2} =2π0π2=2π\frac{2π-0}{π^2}=\frac2π

At x=ln(0.25)

dydx=2ln0.25cos(2×ln0.25)sin(2×ln0.25)(ln0.25)2\frac{dy}{dx}=\frac{2ln0.25cos(2×ln0.25)-sin(2×ln0.25)}{(ln0.25)^2}

dydx=1.415\frac{dy}{dx}=-1.415


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