What are the dimensions of a rectangular field of area A, that requires the least
amount of fencing?
length of fencing:
L=2(x+y)L=2(x+y)L=2(x+y)
area:
A=xy ⟹ y=A/xA=xy\implies y=A/xA=xy⟹y=A/x
L=2(x+A/x)L=2(x+A/x)L=2(x+A/x)
L′(x)=2(1−A/x2)=0L'(x)=2(1-A/x^2)=0L′(x)=2(1−A/x2)=0
x=y=Ax=y=\sqrt Ax=y=A
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