For every function f(x) that is smoothly continuous on (a,b], the average rate of change of f(x) from x = a to x = b, approaches the instantaneous rate of change at x = a as x approaches a from the left.
Please explain this with a graph
Expert's answer
Average rate of change:
(f(b)−f(a))/(b−a)=f′(a)
since x=a+ , which is in the interval [a,b].
If b=a+h where h is very small,
f′(a)=(f(a+h)−f(a))/hash→0
by definition of derivative (instantaneous rate of change).
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