Answer to Question #278396 in Calculus for MGEY

Question #278396

Determine the length of the arc (in radian measure) and the measure of the angle (in radian degree measures) generated by a point that starts (1,0)and terminates at the following:




1. Positive x-axis



2. Negative x-axis



3.Positive y-axis



4.Negative y-axis

1
Expert's answer
2021-12-13T17:41:58-0500

The circumstance "(2\u03c0r)" of a unit circle is "2\u03c0(1) = 2\u03c0."

1. An angle starting at Cartesian point "(1,0)" and terminating at the positive "x" - axis would represent angle of "2\\pi" radians, this would be complete circumstance arc length, that is "2\\pi" radians. We can consider the angles of "2\\pi n" radian, "n\\in \\N" and the corresponding lengths of arc of "2\\pi n" unis of length.


2. An angle starting at Cartesian point "(1,0)" and terminating at the negative "x" - axis would represent angle of "\\pi" radians, this would be complete the half of circumstance arc length, that is "\\pi" radians. We can consider the angles of "\\pi+2\\pi n" radian, "n\\in \\N" and the corresponding lengths of arc of "\\pi+2\\pi n" unis of length.


3. An angle starting at Cartesian point "(1,0)" and terminating at the positive "y" - axis would represent angle of "\\pi\/2" radians, this would be complete the 1/4 of circumstance arc length, that is "\\pi\/2" radians. We can consider the angles of "\\pi\/2+2\\pi n" radian, "n\\in \\N" and the corresponding lengths of arc of "\\pi\/2+2\\pi n" unis of length.


4. An angle starting at Cartesian point "(1,0)" and terminating at the negative "y" - axis would represent angle of "3\\pi\/2" radians, this would be complete the 3/4 of circumstance arc length, that is "3\\pi\/2" radians. We can consider the angles of "3\\pi\/2+2\\pi n" radian, "n\\in \\N" and the corresponding lengths of arc of "3\\pi\/2+2\\pi n" unis of length.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog