Answer to Question #268872 in Calculus for Bhuvana

Question

 Show, by changing to polar coordinates, that Z a sin β

Z

√

a2−y2

y cot β

ln (x

2 + y

2

) dx dy = a

2β(ln a − 1/2), where a > 0 and

0 < β < π/2. Rewrite the Cartesian integral with the order of integration reversed.