use the Leibniz sign.
1. limk→œαkk/2=0
if α<1 then the row converges
limk→œαkk/2=œ
If α>1 then the row diverges.
limk→œ∣αkk/2∣=œ
If α<0 the series converges conditionally.
limk→œ∣αkk/2∣=0
If 0<α<1
the series converges absolutely
2. limk→œαk/k=0
If α<1
then the row converges absolutely
limk→œαk/k=œ
If α>1 then the row diverges
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