Question

f is a function defined by : f(x) = x^2-3.

Find f(0), f(2) and f(4).

Answer 1

Given that $f(x)=x^2-3$

Put $x=0,$ we get:

$f(0)=(0)^2-3=-3$

Put $x=2,$ we get:

$f(2)=(2)^2-3=1$

Put $x=4,$ we get:

$f(4)=(4)^2-3=13$