Answer to Question #262164 in Calculus for Aashish

Question #262164

f is a function defined by : f(x) = x^2-3.

Find f(0), f(2) and f(4).

Expert's answer

Given that "f(x)=x^2-3"

Put "x=0," we get:

"f(0)=(0)^2-3=-3"

Put "x=2," we get:

"f(2)=(2)^2-3=1"

Put "x=4," we get:

"f(4)=(4)^2-3=13"

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