Question #262382

Consider a moving body B whose position at time t is given by R(t)=t2 i+t3 j+3 tk .

[Then V (t) = dR(t) / dt and A(t) = dV (t)/dt denote, respectively, the velocity and acceleration of B.]

When t = 1, find for the body B:

(a) position (b) velocity v (c) speed s (d) acceleration a


1
Expert's answer
2021-11-08T16:45:28-0500

(a)Position=R(t)=t2i+t3j+3tk(a) Position = R(t) = t² i + t³ j + 3t k

(b)Velocity,V(t)=dR(t)dt=2ti+3t2j+3k(b) Velocity, V(t)= \frac{dR(t)}{dt} = 2ti+3t²j+3k

(c)Speed=v(t)=(2t)2+(3t2)2+32(c) Speed = |v(t)| = \sqrt{(2t)²+(3t²)²+3²}


(d)Acceleration,A(t)=dV(t)dt=2i+6tj(d) Acceleration, A(t)= \frac{dV(t)}{dt} = 2i + 6tj


When t=1t = 1


(a)Position=12i+13j+3(1)k=i+j+3k(a) Position = 1²i+1³j+3(1)k = i+j+3k


(b)Velocity=2(1)i+3(1)2j+3k=2i+3j+3k(b) Velocity = 2(1)i+3(1)²j+3k = 2i+3j+3k


(c)Speed=(2(1))2+(3(1)2)2+32=4+9+9=22(c) Speed = \sqrt{(2(1))²+(3(1)²)²+3²} = \sqrt{4+9+9} = \sqrt{22}


(d)Acceleration=2i+6(1)j=2i+6j(d) Acceleration = 2i + 6(1)j = 2i+6j






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