Answer to Question #259233 in Calculus for Emmanuel

Question

If F(t) = 4t^2i - tj + t^2k and G(t) = ti + 2t^2j + 4 sin t k, then find (cos t F)

Answer 1

$F(t) = 4t^2\hat{i} - t \hat{j} + t^2\hat{k}\\G(t) = t\hat{i} + 2t^2\hat{j} + 4 sin t \hat{k}\\ \therefore F.G=4t^3-2t^3+4(sint)t^2=2t^3+4t^2(sint)$