Question #259189

An object in free fall from

50 m high, so the height is

when t is h(t) = 50 – 4.9t2

.

What is the speed at

t = 2?

2. Determine the equation of the tangent line

on the curve y = x3 at the point (2.8)


1
Expert's answer
2021-11-02T16:12:26-0400

1.

speed:

v(t)=h(t)=9.8tv(t)=h'(t)=-9.8t

v(2)=9.82=19.6v(2)=9.8\cdot 2=19.6 m/s


2.

yy0=f(x0)(xx0)y-y_0=f'(x_0)(x-x_0)

f(x)=3x2f'(x)=3x^2

f(2)=322=12f'(2)=3\cdot 2^2=12


y8=12(x2)y-8=12(x-2)

y=12x16y=12x-16


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