Question #249912
Find the area of the triangle formed from the coordinate axes and the tangent line to the curve
1
Expert's answer
2021-10-18T07:39:27-0400

tangent line to the curve at point (x0, y0):

yy0=f(x0)(xx0)y-y_0=f'(x_0)(x-x_0)


intersections of tangent line with axes:

y=0    y0=f(x0)(xx0)y=0\implies -y_0=f'(x_0)(x-x_0)

x=y0/f(x0)+x0x=-y_0/f'(x_0)+x_0


x=0    y=f(x0)x0+y0x=0\implies y=-f'(x_0)x_0+y_0


So, the area of the triangle:

S=xy/2=(y0/f(x0)+x0)(f(x0)x0+y0)/2S=|xy|/2=|(-y_0/f'(x_0)+x_0)(-f'(x_0)x_0+y_0)|/2


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