(i)Let f(x)=tanx,then f(0)=0fā²(x)=sec2x=1+tan2xāfā²(0)=1fā²ā²(x)=2secx(1+tan2x)āfā²ā²(0)=2The Maclaurin series expansion istanx=f(0)+xfā²(0)+2!x2āfā²ā²(x)+3!x3āfā²ā²(x)+ā¦=x+3x3ā+o(x3)
(ii)Put x=31āā“tan(31ā)=31ā+31ā(31ā)3+...=31ā+811ā=8128ā