Consider the function π¦ = tan (π₯)
a) Show that the first two non-zero terms in the Maclaurin series of π¦ are "\ud835\udc65 + 1\/3 \ud835\udc65 ^3" β¦
b) Use the first two terms of the Maclaurin series of π¦ to estimate "tan ( 1\/3 )"
"(i) Let \\ f(x)=\\tan x, then \\ f(0)=0 \\\\\nf^{\\prime}(x)=\\sec ^{2} x=1+\\tan ^{2} x \\\\\n \\Rightarrow f^{\\prime}(0)=1 \\\\\nf^{\\prime \\prime}(x)=2 \\sec x\\left(1+\\tan ^{2} x\\right)\\\\\n \\Rightarrow f^{\\prime \\prime}(0)=2 \\\\\n\nThe \\ Maclaurin \\ series \\ expansion \\ is \\\\\n \n\\tan x=f(0)+x f^{\\prime}(0)+\\frac{x^{2}}{2 !} f^{\\prime \\prime}(x)+\\frac{x^{3}}{3 !} f^{\\prime \\prime}(x)+\\ldots \\\\\n=x+\\frac{x^{3}}{3}+o\\left(x^{3}\\right)"
"(ii) Put \\ x=\\frac{1}{3}\\\\\n\\therefore tan(\\frac{1}{3})=\\frac{1}{3}+\\frac{1}{3}(\\frac{1}{3})^3+...\\\\\n=\\frac{1}{3}+\\frac{1}{81}\\\\\n=\\frac{28}{81}"
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