Answer to Question #213231 in Calculus for Sarita bartwal

Question

The function f: R^2 to R , defined by f(x,y)= 1-y^2+x^2, has an extremum at (0,0).

True or false with full explanation

Answer 1

ANSWER.

The function $f(x,y)=1-{ y }^{ 2 }+{ x }^{ 2 }$ has no an extremum at the point (0,0).

EXPLANATION.

Since $f(0,y)=1-{ y }^{ 2 }\le 1=f(0,0)$ and 

$f(x,0)=1+{ x }^{ 2 }\ge 1=f(0,0)$

 then by the definition of the extremum of the function $f$ has no extremum at the point (0,0).