Answer to Question #213181 in Calculus for renz ash

Question #213181

question #213175

Expert's answer

Here is the answer of your ques. 213175

Total Volume of box V = "b(b+1)(b+4)=b(b^2+5b+4)=b^3+5b^2+4b"

Differentiate V w.r.t. b-

"\\dfrac{dV}{db}=3b^2+10b+4"

Hence Volume is increasing at "3b^2+10b+4"

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