Determine the location and values of the absolute maximum and absolute
minimum for the given function:
𝑓(𝑥) = (−𝑥 + 2)⁴, 𝑤ℎ𝑒𝑟𝑒 0 ≤ 𝑥 ≤ 3
f(x)=(-x+2)⁴ , 0 ≤ 𝑥 ≤ 3
d/dx= 4(-x+2)³
d/dx=0
4(-x+2)³=0
-x+2=0; x=2
f(0)=(0+2)⁴=(2)⁴=16
the absolute minimum point is therefore at x=2 where the value is 0.
the absolute maximum point is at x=0 where the value is 16
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