The point
(π/6 , 1/2)
is on a curve and at any point on the curve, the slope of the tangent line is given by
−2 sin(2x)
. Find an equation of the curve.
Given point is (π/6,1/2)
Given slope of tangent line is -2sin(2x)
So, dy/dx = -2sin(2x)
dy = -2sin(2x) dx
Integrating on both sides with respect to x
∫ dy = (-2) ∫ sin(2x) dx
y = (-2)(-1/2) cos(2x) + C
y = cos(2x) + C
Put (π/6,1/2) in above curve
(1/2) = cos(2*π/6) + C
(1/2) = (1/2) + C
C = 0
Thus, The equation of curve is y = cos(2x)
Comments
Leave a comment