Here,
F=2xzi−xj+y2k
The region V is covered
(a) by keeping x and y fixed and integrating from z=x2 to z=4 (base to top of column PQ),
(b) then by keeping x fixed and integrating from y=0 to y=6 (R to S in the slab)
(c) finally integrating from x=0 to x=2 (wherez=x2 meets z=4)
Then the required integral is :
∫∫∫V Fdv=∫x=02∫y=06∫x24(2xzi−xj+y2k)dzdydx
=i∫02∫06∫x24(2xz)dzdydx−j∫02∫06∫x24(x)dzdydx+k∫02∫06∫x24(y2)dzdydx =128i−24j+384k
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