Find the minimum value of the function
f(x, y) = x2 + 2y2 on the circle x2 + y2 = 1.
Solve equations using Lagrange multipliers
Constraint:
Using Lagrange multipliers,
which become
From (1) we have . If x=0, then (11) gives y=±1. If
λ=1, then y=0 from 2, so then (11) gives x=±1. Therefore f
has possible extreme values at the points
Evaluating f at these four points, we find that
• f(0,1)=2
• f(0,-1)=2
• f(1,0)=1
• f(-1,0)=1
Therefore the maximum value of f on the circle
and the minimum value is
Comments