Given, F(x,y,z)=xzi−yzk and line segment c from (3,0,1) to (-1,2,0).
Then,
r(t)=(1−t)<3,0,1>+t<−1,2,0>=<3−4t,2t,1−t>Differentiate with respect to t,dtdr=<−4,2,−1>dr=(−4i+2j−k)dtNow, F(r(t))=(3−4t)(1−t)i−2t(1−t)k=(3t2−7t+3)i+(2t2−2t)kTherefore,∫F.dr=[(3t2−7t+3)i+(2t2−2t)k].[−4i+2j−k]dt=∫01−4(3t2−7t+3)−(2t2−2t)dt=∫01−14t2+30t−12dt=[−314t3+15t2−12t]01=3−5
Thus,the requrired answer is 5/3.
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