Question #177465

Find a function (f) that satisfies the equation ∫_0^x▒〖f(t)dt=2cos x+3x-2〗


1
Expert's answer
2021-04-15T07:40:36-0400

Solution

As I correctly understand the formula in the question is 0xf(t)dt=2cosx+3x2\int_0^xf(t)dt = 2cosx+3x-2 .

If F(x)=0xf(t)dtF(x) = \int_0^xf(t)dt then f(x) = F’(x).

Therefore f(x) = d(2cosx+3x-2)/dx = -2sinx+3.

Let's check

0xf(t)dt=0x(2sint+3)dt=(2cost+3t)0x=2cosx+3x2cos0=2cosx+3x2\int_0^xf(t)dt = \int_0^x(-2sint+3)dt = (2cost+3t)|_0^x = 2cosx+3x-2cos0 = 2cosx+3x-2

Answer

f(x) = -2sinx+3


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