Obtain a four-term Taylor polynomial approximation valid near x = 0 for each (1+ x)-⅓. Estimate the range of x over which three term polynomials will give two decimal accuracy.
Given, expression is-
"f(x)=(1+x)^{-\\frac{1}{3}}"
On expanding the expression, we get the four term Taylor polyomial
"f(x)=1-\\dfrac{1}{3}x+\\dfrac{2}{9}x^2-\\dfrac{14}{81}x^3"
Range i.e. Region of convergence of x is |x|<1
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