Question #166671

Denote by π‘„𝑅 and π‘† the projections of the point P=(βˆ’2,3,βˆ’4) onto the π‘₯𝑦 plane, the π‘¦π‘§ plane, and the π‘₯𝑧 plane, respectively. Which of the following line segments has the greatest length?


1
Expert's answer
2021-02-25T05:08:42-0500

Solution:

We know that xyxy -plane is described by equation z=0z=0 .

So, projection of P(βˆ’2,3,βˆ’4)P(-2,3,-4) on xyxy -plane is Q(βˆ’2,3,0)Q(-2,3,0) .

We know that yzyz -plane is described by equation x=0x=0 .

So, projection of P(βˆ’2,3,βˆ’4)P(-2,3,-4) on yzyz -plane is R(0,3,βˆ’4)R(0,3,-4) .

We know that xzxz -plane is described by equation y=0y=0 .

So, projection of P(βˆ’2,3,βˆ’4)P(-2,3,-4) on xzxz -plane is S(βˆ’2,0,βˆ’4)S(-2,0,-4) .

Now, we find their distances or length with O(0,0,0)O(0,0,0) using distance formula.

QO=(βˆ’2βˆ’0)2+(3βˆ’0)2+(0βˆ’0)2=4+9=13QO=\sqrt{(-2-0)^2+(3-0)^2+(0-0)^2}=\sqrt{4+9}=\sqrt{13}

RO=(0βˆ’0)2+(3βˆ’0)2+(βˆ’4βˆ’0)2=9+16=25RO=\sqrt{(0-0)^2+(3-0)^2+(-4-0)^2}=\sqrt{9+16}=\sqrt{25}

SO=(βˆ’2βˆ’0)2+(0βˆ’0)2+(βˆ’4βˆ’0)2=4+16=20SO=\sqrt{(-2-0)^2+(0-0)^2+(-4-0)^2}=\sqrt{4+16}=\sqrt{20}

Clearly, 25\sqrt{25} is greater, thus RO is the longest length.


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