Evaluate the integral of (z+2)/(z²+4z) dz from -3 to 2
∫−32(z+2)z2+4zdz\int_{-3}^{2} \frac{(z+2)}{z^2+4z}dz∫−32z2+4z(z+2)dz = Diverges
ans: log(2)
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