Evaluate the ∫(t³+3t)/(t²+1)dt
Let "I=\\int \\dfrac{t^3+3t}{t^2+1} dt"
First performing long division, we get
"I=\\int (t+\\dfrac{2t}{t^2+1} )dt"
On integrating
"I=\\dfrac{t^2}2+\\log|t^2+1|+C"
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