Let {an}∞n=1 be a convergent sequence with limit L such that an ≤ B forevery n≥N for some N ∈ N and some B ∈ R. Prove that L ≤ B
We have that limn→∞an=L\lim \limits_{n \to \infty} a_n = Ln→∞liman=L
Also, an≤Ba_n \leq Ban≤B
Taking limits we have limn→∞an≤limn→∞B\lim \limits_{n \to \infty} a_n \leq \lim \limits_{n \to \infty} Bn→∞liman≤n→∞limB
Hence L≤limn→∞B=BL \leq \lim \limits_{n \to \infty} B = BL≤n→∞limB=B
As desired
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