Question #159442

Let {an}∞n=1 be a non-decreasing (resp. non-increasing) sequence which converges to a. Then prove that an ≤ a (resp. a ≤ an) for every n ∈ N


1
Expert's answer
2021-02-01T06:37:12-0500

Let (an)n=1(a_n)_{n=1}^{\infty} be a non-decreasing (resp. non-increasing) sequence which converges to

aa, so we have that

limnan=a\lim \limits_{n \to \infty} a_n = a ...()... (*)

Also, anan+1a_n \leq a_{n+1} (resp. anan+1)n1a_n \geq a_{n+1}) \forall n \geq 1

So we have from ()(*) that limnana\lim \limits_{n \to \infty} a_n \leq a

(resp. limnana\lim \limits_{n \to \infty} a_n \geq a ).

And since (an)n=1(a_n)_{n=1}^{\infty} is non-decreasing (resp. non-increasing), we have that anaa_n \leq a (resp. anaa_n \geq a ) As desired


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