Question #159440

A sequence is bounded if and only if it is both bounded above and bounded below


1
Expert's answer
2021-02-01T07:37:49-0500

Let {an}n=1\{a_n\}_{n=1}^{\infty} be a bounded sequence, that is there exists a constant M>0, such that anM|a_n|\leq M .

Then anMa_n\leq M and, hence, this sequence is bounded above.

We have also anMa_n\geq -M and, hence, this sequence is bounded below.


Let {an}n=1\{a_n\}_{n=1}^{\infty} be a sequence bounded above and bounded below.

Tthat is there exist two constants M1 and M2 such that

M1anM2M_1\leq a_n\leq M_2

Let M=max{M1,M2}M=\max\{|M_1|, |M_2|\} . Then we have

anM2M2max{M1,M2}=Ma_n\leq M_2\leq |M_2|\leq \max\{|M_1|, |M_2|\}= M and

anM1M1max{M1,M2}=Ma_n\geq M_1\geq -|M_1|\geq -\max\{|M_1|, |M_2|\}= -M

Hence, anM|a_n|\leq M and the sequence {an}n=1\{a_n\}_{n=1}^{\infty} is bounded.


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