Let f be a function such that each point (x,y) on the graph of f, the slope given by dy/dx = y^2-x. The graph of f passes through the point (1,2) and is concave down on the interval 1<x<1.5. Let k be the approximation of f (1.2) found by using the locally linear approximation of f at x=1. Which of the following statements about k is true?
a) k=5.6 and is an overestimate of f(1.2)
b) k=5.6 and is an underestimate of f(1.2)
c) k-2.6 and is an overestimate of f(1.2)
d) k=2.6 and is an underestimate of f(1.2)
Since the function is concave down, it is overestimated and "f''(x)<0"
"y''=2yy'-1"
Then:
for "k=f(1.2)=5.6" :
"2yy'-1=2\\cdot5.6\\cdot(5.6^2-1.2)-1>0"
for "k=f(1.2)=-2.6" :
"2yy'-1=-2\\cdot2.6\\cdot(2.6^2-1.2)-1<0"
Answer: statement (c) is true.
Comments
Dear Stephen, according to conditions of the question, k is the approximation of f (1.2) found by using the locally linear approximation of f at x=1. It was computed that k=f(1.2)=5.6.
Where did you get 5.6 from?
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