Question #155472

Let f be a function such that each point (x,y) on the graph of f, the slope given by dy/dx = y^2-x. The graph of f passes through the point (1,2) and is concave down on the interval 1<x<1.5. Let k be the approximation of f (1.2) found by using the locally linear approximation of f at x=1. Which of the following statements about k is true?


a) k=5.6 and is an overestimate of f(1.2)

b) k=5.6 and is an underestimate of f(1.2)

c) k-2.6 and is an overestimate of f(1.2)

d) k=2.6 and is an underestimate of f(1.2)


1
Expert's answer
2021-01-17T18:05:02-0500

Since the function is concave down, it is overestimated and f(x)<0f''(x)<0

y=2yy1y''=2yy'-1

Then:

for k=f(1.2)=5.6k=f(1.2)=5.6 :

2yy1=25.6(5.621.2)1>02yy'-1=2\cdot5.6\cdot(5.6^2-1.2)-1>0

for k=f(1.2)=2.6k=f(1.2)=-2.6 :

2yy1=22.6(2.621.2)1<02yy'-1=-2\cdot2.6\cdot(2.6^2-1.2)-1<0


Answer: statement (c) is true.


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Comments

Assignment Expert
01.03.21, 14:50

Dear Stephen, according to conditions of the question, k is the approximation of f (1.2) found by using the locally linear approximation of f at x=1. It was computed that k=f(1.2)=5.6.

Stephen
01.03.21, 03:47

Where did you get 5.6 from?

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