Question #155402

Sketch the graph of

y=1/π+r2

by finding the domain, symmetries, critical points, inflection points,

intercept points, asymptotes, extremas, intervals on which the function is increasing or decreasing,

concave up or down.




1
Expert's answer
2021-01-20T02:52:10-0500

y=1π+r2y=\frac{1}{\pi+r^2}


Domain: r(,)r\isin(-\infin,\infin)


Asymptote:

limrf(r)=limrf(r)=0\displaystyle\lim_{r\to -\infin}f(r)=\displaystyle\lim_{r\to \infin}f(r)=0

Horizontal asymptote is y=0y=0


Symmetry:

there is symmetry respect to y-axis: f(r)=f(r)f(r)=f(-r)


Critical point, extrema:

y=2r(π+r2)2=0    r=0y'=-\frac{2r}{(\pi+r^2)^2}=0\implies r=0

the function is increasing on r(,0)r\isin(-\infin,0) , y>0y'>0

the function is decreasing on r(0,)r\isin(0,\infin) , y<0y'<0

maxima is (0,1/π)(0,1/\pi)


Inflection points:

y=2(π+r2)22r4r(π+r2)(π+r2)4=0y''=-\frac{2(\pi+r^2)^2-2r\cdot4r(\pi+r^2)}{(\pi+r^2)^4}=0

4r2πr2=04r^2-\pi-r^2=0

r=±π/3r=\pm\sqrt{\pi/3}

Inflection points are (π/3,1π+3),(π/3,1π+3)(\sqrt{\pi/3},\frac{1}{\pi+3}), (-\sqrt{\pi/3},\frac{1}{\pi+3})


Intercept point:

r=0    y=1/πr=0\implies y=1/\pi

y-intercept point is (0,1/π)(0,1/\pi)

there no x-intercepts

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