Answer to Question #151211 in Calculus for jack forde

Question

Find the inverse, g−1(t), when g(t) is given by 1/5t+10.

g−1(t)=

Answer 1

Solution:

$g(t)= \dfrac{1}{5t+10}$

let`s call g(t) as y:

$y= \dfrac{1}{5t+10}$ then $( \dfrac{1}{y}) -10=5t$

$t = \dfrac{1}{5y}-2$

Answer:

$g(t)^{-1} = \dfrac{1}{5t}-2$ is inverse.