Question #135771

Find the limits, if they exist, or type DNE for any which do not exist.

lim(x,y)→(0,0) 5x^2/(x^2+5y^2)
1) Along the x-axis:

2) Along the y-axis:

3) Along the line y=mx :

4) The limit is:

Expert's answer

(1)lim⁡(x,y)→(0,0)(5x2x2+5y2)Along thexaxis,y=0lim⁡(x,y)→(0,0)(5x2x2+5y2)=lim⁡(x,y)→(0,0)(5x2x2+5(0)2)=lim⁡(x,y)→(0,0)(5x2x2)=51=5(2)Along theyaxis,x=0lim⁡(x,y)→(0,0)(5x2x2+5y2)=lim⁡(x,y)→(0,0)(5(0)2((0))2+5y2)=0(3)Along the liney=mxlim⁡(x,y)→(0,0)(5x2x2+5y2)=lim⁡(x,y)→(0,0)(5x2x2+5m2x2)=lim⁡(x,y)→(0,0)(51+5m2)=51+5m2(4)Since the results in(1),(2),(3)are unequal,the limit does not exist.(1)\\\lim_{(x, y) \rightarrow (0,0)}\left( \frac{5x^2}{x^2 + 5y^2}\right) \\ \textsf{Along the} \hspace{0.1cm} x\hspace{0.1cm} \textsf{axis}, y = 0\\ \begin{aligned} \lim_{(x, y) \rightarrow (0,0)}\left( \frac{5x^2}{x^2 + 5y^2} \right) &= \lim_{(x, y) \rightarrow (0,0)}\left( \frac{5x^2}{x^2 + 5(0)^2}\right) \\&= \lim_{(x, y) \rightarrow (0,0)} \left(\frac{5x^2}{x^2} \right)\\& = \frac{5}{1} = 5 \end{aligned}\\ (2)\\\textsf{Along the} \hspace{0.1cm} y\hspace{0.1cm} \textsf{axis}, x = 0\\ \begin{aligned} \lim_{(x, y) \rightarrow (0,0)}\left( \frac{5x^2}{x^2 + 5y^2} \right)&= \lim_{(x,y) \rightarrow (0,0)}\left( \frac{5(0)^2}{((0))^2 + 5y^2}\right) \\&= 0 \end{aligned}\\ (3)\\\textsf{Along the line} \hspace{0.1cm} y = mx\\ \begin{aligned} \lim_{(x, y) \rightarrow (0,0)} \left(\frac{5x^2}{x^2 + 5y^2}\right) &= \lim_{(x, y) \rightarrow (0,0)}\left( \frac{5x^2}{x^2 + 5m^2x^2}\right) \\&= \lim_{(x, y) \rightarrow (0,0)}\left( \frac{5}{1 + 5m^2}\right) \\& = \frac{5}{1 + 5m^2} \end{aligned}\\ (4) \\\textsf{Since the results in} \hspace{0.1cm}(1), (2), (3) \hspace{0.1cm}\textsf{are unequal}, \\\textsf{the limit does not exist.}


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