since function
"f(x,y)=c"
"c=\\frac{2y+x}{x-y-3}"
Since this curve passing through (1,2)
substitute x=1 and y=2
then,
"c=\\frac{4+1}{1-2-3}"
c="\\frac{-5}{4}"
so
"\\frac{-5}{4}=\\frac{2y+x}{x-y-3}"
-5x+5y+15=8y+4x
9x+3y=15
so
3x+y=5
y=5-3x
This is the required curve.
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