Question #135762

For the function (2y+x)/(x-y-3)

write out an equation for a level curve for which f(x,y) = C. Your final equation should be of the form y = f(x,C). What is the level curve that goes through the point (1,2)?

Expert's answer

since function

f(x,y)=cf(x,y)=c


c=2y+xx−y−3c=\frac{2y+x}{x-y-3}


Since this curve passing through (1,2)

substitute x=1 and y=2

then,

c=4+11−2−3c=\frac{4+1}{1-2-3}


c=−54\frac{-5}{4}


so

−54=2y+xx−y−3\frac{-5}{4}=\frac{2y+x}{x-y-3}


-5x+5y+15=8y+4x


9x+3y=15

so

3x+y=5

y=5-3x

This is the required curve.


LATEST TUTORIALS
APPROVED BY CLIENTS