Question

Evaluate the limit, if it exists. If not, enter "n" below.
limh→0
(2+h)^3 −8
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h
(the whole thing is divided by h)

Answer 1

$$\lim_{h\to0} \dfrac{(2+h)^3-8}{h} = \\ =\lim_{h\to0} \dfrac{8+12h+6h^2+h^3-8}{h} = \\ =\lim_{h\to0} (12+6h+h^2) = 12$$