Question #128014

A company estimates that the demand for its product fluctuates with the price it charges. The demand function is given as:

q = 100,000 - 200p


Where .q. equals the number of units demanded and .p. equals the price in rupees. The total cost of producing q units of the product is estimated by the function:


C = 150,000 + 100q + 0.003q2

Required:


a.Determine how many units of q should be produced in order to maximize annual profit?

b.What price should be charged?

c.What is the annual profit expected to equal?

Expert's answer

Profit=Revenue−CostProfit=Revenue-Cost

q=100000−200p=>p(q)=500−0.005qq = 100000 - 200p=>p(q)=500-0.005q

R(q)=p(q)⋅q=500q−0.005q2R(q)=p(q)\cdot q=500q-0.005q^2

P(q)=R(q)−C(q)=P(q)=R(q)-C(q)==500q−0.005q2−(150000+100q+0.003q2)==500q-0.005q^2-(150000 + 100q + 0.003q^2)==400q−0.008q2−150000=400q-0.008q^2-150000

a.

P′(q)=400−0.016qP'(q)=400-0.016q

Find the critical number(s)

P′(q)=0=>400−0.016q=0=>q=25000P'(q)=0=>400-0.016q=0=>q=25000

P′′(q)=−0.016<0P''(q)=-0.016<0

The function P(q)P(q) has a local maximum at q=25000.q=25000.

Since the function P(q)P(q) has the only extremum, then the function P(q)P(q) has the absolute maximum at q=25000.q=25000.

A company has to produce q=25000q=25000 units in order to maximize annual profit.


b.

p(25000)=500−0.005(25000)=375p(25000)=500-0.005(25000)=375

The price is Rs375.

c.


P(25000)=400(25000)−0.008(25000)2−150000=P(25000)=400(25000)-0.008(25000)^2-150000=

=4850000=4850000

The expected annual profit is Rs4,850,000.


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