Question #127866
A window consists of a rectangular piece of clear glass with a semicircular piece of
colored glass on top; the colored glass transmits only 1/2 as much light per unit area as the the clear
glass. If the distance from top to bottom (across both the rectangle and the semicircle) is 2 meters and
the window may be no more than 1.5 meters wide, find the dimensions of the rectangular portion of the
window that lets through the most light.
1
Expert's answer
2020-07-29T14:39:31-0400

Let 𝑟 be a radius of a semicircle, HH be a distance from top to bottom. Then the horizontal side of the rectangle is equal 2𝑟, vertical side of the rectangle is equal 𝐻 − 𝑟. Effective area of the window is


S=Srect+kSsemi=2r(Hr)+k12πr2S=S_{rect}+kS_{semi}=2r(H-r)+k\cdot{1\over 2}\pi r^2

Given


H=2 m,k=12,0<2r1.5 mH=2\ m, k={1\over 2}, 0<2r\leq 1.5\ m

Substitute


S=S(r)=2r(2r)+1212πr2S=S(r)=2r(2-r)+{1\over 2}\cdot{1\over 2}\pi r^2

S=S(r)=4r2r2+14πr2,0<r0.75S=S(r)=4r-2r^2+{1\over 4}\pi r^2, 0<r\leq0.75

Find the critical number(s)


S=(4r2r2+14πr2)=44r+12πrS'=(4r-2r^2+{1\over 4}\pi r^2)'=4-4r+ {1\over2}\pi r

S=0=>44r+12πr=0S'=0=>4-4r+ {1\over2}\pi r=0r=88πr={8\over 8-\pi}

First derivative test

If 0<r<88π,S>0,S0<r<\dfrac{8}{8-\pi}, S'>0, S increases.

If r>88π,S<0,Sr>\dfrac{8}{8-\pi}, S'<0, S decreases.

The function S(r)S(r) has a local maximum at r=88π.r=\dfrac{8}{8-\pi}.

Since the function SS has the only extremum, then the function SS has the absolute maximum r=88π.r=\dfrac{8}{8-\pi}.


88π>1.5\dfrac{8}{8-\pi}>1.5

Hence we have to take r=0.75mr=0.75 m

The width of the rectangular portion of the window  is 2r=1.5m.2r=1.5m.

The height of the rectangular portion of the window  is 20.75m=1.25m2-0.75m=1.25m

The dimensions of the rectangular portion of the window that lets through the most light are


1.5m×1.25m1.5m\times1.25m


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