Question #127866

A window consists of a rectangular piece of clear glass with a semicircular piece of

colored glass on top; the colored glass transmits only 1/2 as much light per unit area as the the clear

glass. If the distance from top to bottom (across both the rectangle and the semicircle) is 2 meters and

the window may be no more than 1.5 meters wide, find the dimensions of the rectangular portion of the

window that lets through the most light.

Expert's answer

Let 𝑟 be a radius of a semicircle, HH be a distance from top to bottom. Then the horizontal side of the rectangle is equal 2𝑟, vertical side of the rectangle is equal 𝐻 − 𝑟. Effective area of the window is


S=Srect+kSsemi=2r(Hr)+k12πr2S=S_{rect}+kS_{semi}=2r(H-r)+k\cdot{1\over 2}\pi r^2

Given


H=2 m,k=12,0<2r1.5 mH=2\ m, k={1\over 2}, 0<2r\leq 1.5\ m

Substitute


S=S(r)=2r(2r)+1212πr2S=S(r)=2r(2-r)+{1\over 2}\cdot{1\over 2}\pi r^2

S=S(r)=4r2r2+14πr2,0<r0.75S=S(r)=4r-2r^2+{1\over 4}\pi r^2, 0<r\leq0.75

Find the critical number(s)


S=(4r2r2+14πr2)=44r+12πrS'=(4r-2r^2+{1\over 4}\pi r^2)'=4-4r+ {1\over2}\pi r

S=0=>44r+12πr=0S'=0=>4-4r+ {1\over2}\pi r=0r=88πr={8\over 8-\pi}

First derivative test

If 0<r<88π,S>0,S0<r<\dfrac{8}{8-\pi}, S'>0, S increases.

If r>88π,S<0,Sr>\dfrac{8}{8-\pi}, S'<0, S decreases.

The function S(r)S(r) has a local maximum at r=88π.r=\dfrac{8}{8-\pi}.

Since the function SS has the only extremum, then the function SS has the absolute maximum r=88π.r=\dfrac{8}{8-\pi}.


88π>1.5\dfrac{8}{8-\pi}>1.5

Hence we have to take r=0.75mr=0.75 m

The width of the rectangular portion of the window  is 2r=1.5m.2r=1.5m.

The height of the rectangular portion of the window  is 20.75m=1.25m2-0.75m=1.25m

The dimensions of the rectangular portion of the window that lets through the most light are


1.5m×1.25m1.5m\times1.25m


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