Let 𝑟 be a radius of a semicircle, "H" be a distance from top to bottom. Then the horizontal side of the rectangle is equal 2𝑟, vertical side of the rectangle is equal 𝐻 − 𝑟. Effective area of the window is
Given
Substitute
"S=S(r)=4r-2r^2+{1\\over 4}\\pi r^2, 0<r\\leq0.75"
Find the critical number(s)
"S'=0=>4-4r+ {1\\over2}\\pi r=0""r={8\\over 8-\\pi}"
First derivative test
If "0<r<\\dfrac{8}{8-\\pi}, S'>0, S" increases.
If "r>\\dfrac{8}{8-\\pi}, S'<0, S" decreases.
The function "S(r)" has a local maximum at "r=\\dfrac{8}{8-\\pi}."
Since the function "S" has the only extremum, then the function "S" has the absolute maximum "r=\\dfrac{8}{8-\\pi}."
Hence we have to take "r=0.75 m"
The width of the rectangular portion of the window is "2r=1.5m."
The height of the rectangular portion of the window is "2-0.75m=1.25m"
The dimensions of the rectangular portion of the window that lets through the most light are
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