1) Given y=C–t+t21 ________(1)
⟹dtdy=(−1)(C−t+t2)−2(−1+2t)=(C−t+t2)21−2t=(1−2t)y2
Hence, y given by (1) is solution of dxdy=(1−2t)y2 .
2) Given y=C+cost1 __________(2)
⟹dtdy=(−1)(C+cost)−2(−sint)=y2sin(t)
Hence, y given by (2) is solution of dtdy=y2sin(t)
Comments