We can integrate the function "(5x-3)^4" by substitution. Set "u=5x-3", then "du=5dx," and "dx=\\frac{du}{5}."
Hence
"\\int (5x-3)^4dx=\\int u^4\\frac{du}{5}=\\frac{1}{5}\\int u^4du=\\frac{1}{5}\\cdot \\frac{u^5}{5}+C=\\frac{u^5}{25}+C="
"=\\frac{(5x-3)^5}{25}+C."
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