f:R→R that is (x,y)↦2xyg:R→R that is (x,y)↦x2+y21)h=f/g=fg=2xyx2+y2h:R∖(0,0)→R∖(0,0) because x2+y2 is not equal to (0,0).The domain of h is R∖(0,0).f:R\to R \ that \ is\ (x,y)\mapsto 2xy\\ g:R\to R \ that\ is \ (x,y) \mapsto x^2+y^2\\ 1) h=f/g=\frac{f}{g}=\frac{2xy}{x^2+y^2}\\ h:R\setminus (0,0)\to R \setminus( 0,0) \ because \ x^2+y^2 \ is \ not \ equal \, to \,(0,0).\\ The\ domain \ of \ h\ is \ R\setminus(0,0).\\f:R→R that is (x,y)↦2xyg:R→R that is (x,y)↦x2+y21)h=f/g=gf=x2+y22xyh:R∖(0,0)→R∖(0,0) because x2+y2 is not equalto(0,0).The domain of h is R∖(0,0).
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