Question #122107

Find the range of the function f defined by f(x,y) = 10-x^2-y^2 for all (x,y) for which x^2+y^2 <=9. Sketch two of its level curves.

Expert's answer

Find the critical points fx=2x=0,fy=2y=0f'_x=-2x=0, f'_y=-2y=0 hence f(0,0)=10f(0,0)=10 ,fmax=10f_{max}=10

On the border of the area f(x,y)=10(x2+y2)f(x,y)=10-(x^2+y^2) hence f(x,y)1andf(x,y)10f(x,y)\geq1\, \text{and} \, f(x,y)\le10

hence fmin=1f_{min}=1

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