Since "\\frac{d}{dx}(xlnx-x)=lnx," then "\\int lnx dx= xlnx-x+C"
Volume of the solid obtained by rotating can be found by formula: "\\pi \\int y^2dx"
Boundaries of integration are "x=1" and "x=e^2".
So:
"V=\\pi \\int\\limits_1^{e^2} (\\sqrt{lnx})^2dx=\\pi\\int\\limits_1^{e^2}lnxdx=\\pi (xlnx-x)\\bigg|_1^{e^2}=\\\\\n\\pi(e^2lne^2-e^2)-\\pi(1ln1-1)=\\pi(e^2+1)"
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